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8c^2+11c+7=6c^2
We move all terms to the left:
8c^2+11c+7-(6c^2)=0
determiningTheFunctionDomain 8c^2-6c^2+11c+7=0
We add all the numbers together, and all the variables
2c^2+11c+7=0
a = 2; b = 11; c = +7;
Δ = b2-4ac
Δ = 112-4·2·7
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{65}}{2*2}=\frac{-11-\sqrt{65}}{4} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{65}}{2*2}=\frac{-11+\sqrt{65}}{4} $
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